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5.2x^2-1.344x-0.1075=0
a = 5.2; b = -1.344; c = -0.1075;
Δ = b2-4ac
Δ = -1.3442-4·5.2·(-0.1075)
Δ = 4.042336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.344)-\sqrt{4.042336}}{2*5.2}=\frac{1.344-\sqrt{4.042336}}{10.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.344)+\sqrt{4.042336}}{2*5.2}=\frac{1.344+\sqrt{4.042336}}{10.4} $
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